求这个产分匹配的设计思路

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SAW的Terminating load impedance: ZL = 150 Ω|| 82 nH (balanced)
这是SAW的
LNA的ZIN Required SAW impedance(parallel model)
f=881MHz 302|-0.67 Ω|pF 这是LAN的
现在求这个产分匹配的设计思路，谢谢了！

matching design epcos SAW tp SP6.doc :

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Epcos SAWTerminating load impedance: ZL = 150 Ω|| 82 nH (balanced)
conversion to single ended equivalentZL = 75 Ω|| 41 nH
Draw this point on Smith(Z0=75) Point:67.66+j22.358
SP6 LNA Zin Required SAW impedance(parallel model) f=881MHzZin=302|-0.67 Ω|pF （ ‘|’ means Parallel？）
conversion to single ended equivalent Zin=151|-1.34 Ω|pF
Draw this point on Smith(Z0=75) Point:68-j74.7

Then need to converse 67.66+j22.358 to 68-j74.7

So, we just need to add a Series capacitance 1.9pF to the differential circuit.
详见附件。大家看看对否？

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