- 易迪拓培训,专注于微波、射频、天线设计工程师的培养
efficiency equation in ADS
is it true?
100*pload_w/(vcc[0]*i_dc.i[::,0])
in my circute gives me 0.002% but in the paper gives 60% why?
do you give me your email to send my file and solve my problem? pleaseeeee
thank you
How do you measure pload_w ? Because pload_w -in generally- is complex and it's got real and imaginary part.Also it has all harmonics including DC.
You do probably an error and therefore you find this number.
In additional to, if the load is complex, you can not find the delivered power to load by V[1]/R.. It will be wrong.
If the load is complex, P_load_del=1/2*real((V_load[1]*cong(I_load[1]))) in Watts.
thank you for your answer. this photo in my equation in shematic in ads for PA J Class. i test your formula and efficiency is the same 0.002%.can you see my formula and give me your idea.
thank you
Hi to all
I didn't try to calculate power efficiency in ADS, but your post interested me :)
My thoughts - you have wrong dc power calculation equations.
If yoi open power amplifier design examples, you'll see:
I don't know what it means, but i really want to understand it.
If your load is complex, then your Vmag and I mag are not in phase.
So your calculation is error.
And, your gain is error, because Pload_W plus 30dB, but Pin_W don't, so if you want to convert to dBm, both should do so.
申明:网友回复良莠不齐,仅供参考。如需专业帮助,请学习易迪拓培训专家讲授的ADS视频培训课程。
上一篇:oscillaror simulation with ADS
下一篇:In ADS, doubts regarding on the degenarated source inductance.
国内最全面、最专业的Agilent ADS培训课程,可以帮助您从零开始,全面系统学习ADS设计应用【More..】
- Agilent ADS教学培训课程套装
- 两周学会ADS2011、ADS2013视频教程
- ADS2012、ADS2013射频电路设计详解
- ADS高低阻抗线微带滤波器设计培训教程
- ADS混频器仿真分析实例视频培训课程
- ADS Momentum电磁仿真设计视频课程
- ADS射频电路与通信系统设计高级培训
- ADS Layout和电磁仿真设计培训视频
- ADS Workspace and Simulators Training Course
- ADS Circuit Simulation Training Course
- ADS Layout and EM Simulation Training Course
- Agilent ADS 内部原版培训教材合集