- 易迪拓培训,专注于微波、射频、天线设计工程师的培养
Balun problem in ADS, plz help
Here is a picture of my circuit:
And I also attached the circuit.
A Marchand has good return loss over only an octave. It is only perfectly matched at one point. I changed a few dimensions and here is one tuned to 4.5 GHz.
Thank you for help
But still I have some questions about your circuit. Balun has three ports, but you just put two ports in the circuit, why? And the value of term2 is 100ohm, why? If I want to have a look at the phase difference between the two outputs, how can I make it?
The balun is really a two port device. The output is balanced (differential mode), the input is single ended grounded (common mode). That is the reason for using a balun. The balun has a 1:2 impedance ratio. The single ended 50 ohms input is transformed to a 100 ohm differential output. The way you draw it in your schematic is somewhat artificial. The way I draw it is how it is actually used.
can you recommend me some books or papers introducing balun basicly? Maybe I am still not very clear about the concepts of balun.
And still the same question: according to your circuit, if I want to take a look at the phase difference between the two balanced outputs, how can I make it?
Thank you.
To measure the phase difference at balanced port make an ac simulation sweeping single end port freq and probing the differential phase at output with the same load (100 Ohm).
Mazz
I will very appreciate if you can give me a ads circuit. I am still puzzled about it.
Thank you.
Tomek
Sorry, I'm not able to give you the circuit.
Please consider that the solution I'm giving is a very simple one.
Mazz
Never mind, thank you anyway
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