How can we calculate the radiated power in CST MWS？

dear friends 
hi 
I embedded an antenna in a lossy medium and I know the S11 and deliver power 1w but i don't know, how should I calculate the radiated power? 
the return loss Figure is resonated at 402MHz to -20dB . 
Is this solution sorrect? 
S11=10log(P(ref)/P(inc)))=> 
-20=10log(P(reflected)/1w)=>P(reflected)=0.01w 
P(inc)=P(radiated)+P(ref)=>P(radiated)=0.99 

but I have a lossy medium in which the antenna is located.that is 
P(radiated)=P(pure_radiation)+P(Loss) 

I know the SAR value 135(mw/g), but I don't know how should I calculate the P(Loss) and then the pure value of the P(pure_radiation). 
so ,what's the solution?

p(accept)=p(incidence)*s21=0.99w
p(pure_radiation)=p(accept)*Q
那有木有Q值啊?
你知道sar没什么用吧，天线一定不是全向的吧，就算是，也反映不到该点的辐射能量密度，算不了辐射功率的吧。

sorry i don't understand  exactly ,would you please explain more?
if the radiation pattern be something like this
how we can calculate the radiated power?

试着翻译一下小编的意思，小编是说把一个天线放置在一块有耗介质内部，现在想得到天线通过有耗介质辐射至自由空间的总功率，是吗?
如果是实际测量，小编要如何得到这个参数?
PS：如果可能的话，用自己的机器敲汉字吧。

I found out how should I calculate the radiated power it is calculated from the radiation efficiency of the antenna
radiation efficiency=P(radiated)/P(delivered)
in which the P(delivered)=1w

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